Phil Hellmuth really wants this 10th bracelet.
After coming thisclose to capturing bracelet number 10 to tie Johnny Chan and Doyle Brunson atop the all-time list in Event #9, Hellmuth now finds himself second overall in chips in Event #24 ($3000 Omaha hi-low).
Throwing all journalistic integrity aside, it’d be a great story to see Hellmuth win this. He’s playing unbelievable poker and to rebound after a crushing defeat just 10 days ago would be an exclamation
point on a career that still likely has [a few more exclamation points in it].
First, Hellmuth will have to get past Scott Clements. Clements cashed earlier in this year’s WSOP in the $2,000 Omaha Hi/Lo event and from the picture of him at right, looks as if he’s capable of killing you win you least expect it.
The rest of the final table chip counts: 2) (the aforementioned) Phil Hellmuth – 158,000, 3) Ronald Matsuura – 120,000, 4) Alex Limjoco – 116,000, 5) Peter Costa – 108,000, 6) Stephen Ladowsky – 97,000, 7) Thor Hansen – 86,000,
Martin Corpuz – 76,000, 9) Brent Carter – 49,000.
* Photo from Poker Pages.
Tagged as:
2006 world series of poker,
2006 WSOP,
most all time wsop bracelets,
Phil Hellmuth